Great Circle Distance Calculation

Oct 15, 2007


Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation

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Great Circle Distance Calculation

Oct 15, 2007

Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation 
 

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Great Circle Distance Function - Haversine Formula

Mar 28, 2007

This function computes the great circle distance in Kilometers using the Haversine formula distance calculation.

If you want it in miles, change the average radius of Earth to miles in the function.

create function dbo.F_GREAT_CIRCLE_DISTANCE
(
@Latitude1 float,
@Longitude1 float,
@Latitude2 float,
@Longitude2 float
)
returns float
as
/*
fUNCTION: F_GREAT_CIRCLE_DISTANCE

Computes the Great Circle distance in kilometers
between two points on the Earth using the
Haversine formula distance calculation.

Input Parameters:
@Longitude1 - Longitude in degrees of point 1
@Latitude1 - Latitude in degrees of point 1
@Longitude2 - Longitude in degrees of point 2
@Latitude2 - Latitude in degrees of point 2

*/
begin
declare @radius float

declare @lon1 float
declare @lon2 float
declare @lat1 float
declare @lat2 float

declare @a float
declare @distance float

-- Sets average radius of Earth in Kilometers
set @radius = 6371.0E

-- Convert degrees to radians
set @lon1 = radians( @Longitude1 )
set @lon2 = radians( @Longitude2 )
set @lat1 = radians( @Latitude1 )
set @lat2 = radians( @Latitude2 )

set @a = sqrt(square(sin((@lat2-@lat1)/2.0E)) +
(cos(@lat1) * cos(@lat2) * square(sin((@lon2-@lon1)/2.0E))) )

set @distance =
@radius * ( 2.0E *asin(case when 1.0E < @a then 1.0E else @a end ))

return @distance

end


Edit: corrected spelling


CODO ERGO SUM

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Oracle

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this is a sfar as I have got with the sql version

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Hi
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Help will be appreciated

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Hi,
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I hope I was enough clear with my poor english.
Thanks All

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Im not getting data when I execute the below 0 Rows:

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Hope someone can solve my problem

I have a working version of the above installed on a win 2000 machine with SQL ver (MSDE2000A.exe)


I purchase a laptop with vista home premium installed on it


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Please can anyone help !!!
and please dont get too technical Im not an expert


Many Thanks
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I am new to data mining so please excuse my ignorance. Lets assume

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- each record consists of 15 columns

- collecting new records( 15 variables) real time

what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).

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thanks.

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Jan 12, 2008

I have a user defined function, I want to determine the distance between the 2 points. I have it working but i'm having a problem getting to print.

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++




Code Snippetcreate function dbo.Distance( @lat1 float , @long1 float , @lat2 float , @long2 float)
returns float

as

begin

declare @DegToRad as float
declare @Ans as float
declare @Miles as float

set @DegToRad = 57.29577951
set @Ans = 0
set @Miles = 0

if @lat1 is null or @lat1 = 0 or @long1 is null or @long1 = 0 or @lat2 is
null or @lat2 = 0 or @long2 is null or @long2 = 0

begin

return ( @Miles )

end

set @Ans = SIN(@lat1 / @DegToRad) * SIN(@lat2 / @DegToRad) + COS(@lat1 / @DegToRad ) * COS( @lat2 / @DegToRad ) * COS(ABS(@long2 - @long1 )/@DegToRad)

set @Miles = 3959 * ATAN(SQRT(1 - SQUARE(@Ans)) / @Ans)

set @Miles = CEILING(@Miles)

return ( @Miles )

end

DECLARE @RC float
EXEC Distance '39.943762', '-78.122265', '32.334709', '-96.633546'
PRINT @RC /* in miles */

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May 31, 2006

Greetings,

We currently use GP 8.00 with the SQL Server 8.0.

We are trying to develop a view based on manfacturing orders - when a finished good is placed on hold and then calculating the componet parts that are on hold.

The calculation runs fine, we multiply end quanity x componet quanity found on the BOM. But we are not getting the correct componet item numbers to display.

Here is the syntax we are using:

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Sam

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Act: Microsoft Server 2005

You need to upgrade to SQL Server 7.0 before continuing".

Why am I get that error message when I have SQL Server 2005 installed?

Can someone point me in the right direction.

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http://search.live.com/macros/sql_server_user_education/booksonline

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DECLARE @Latitude NUMERIC(9, 6), @Longitude NUMERIC(9, 6)

DECLARE @MyLatitude NUMERIC(9, 6), @MyLongitude NUMERIC(9, 6)
Set @Latitude = 42.329596;
Set @Longitude = -83.709286;
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Jun 24, 2005

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CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999))
RETURNS int
AS
BEGIN
DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int,
@cv0 varbinary(8000), @cv1 varbinary(8000)
SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0
WHILE @j <= @s2_len
SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1
WHILE @i <= @s1_len
BEGIN
SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1
WHILE @j <= @s2_len
BEGIN
SET @c = @c + 1
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) +
CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END
IF @c > @c_temp SET @c = @c_temp
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1
IF @c > @c_temp SET @c = @c_temp
SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1
END
SELECT @cv1 = @cv0, @i = @i + 1
END
RETURN @c
END

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