I Am Looking For The Function That Is The Same As InStr In Access

Jan 29, 2001

Hello there...
I am looking for the function that is the same as InStr in Access for SQL server. I have a column that has format like this.. Lastname,Firstname Middlename...
This column doesn't separate each one of them. However I need to separate Lastname and Firstname and Middlename.. I was told that in Access there is function(InStr) that can find a position of comma and separate it as Lastname like that....
I was searching BOL but I couldn't find like this function in SQL Server..
So I need help:-))))
Because everybody has a different length of the lastname, I have a problem.
I can not use SUBSTRING or LEFT or RIGHT because of the varying position of comma ...

Thanks in advance

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Instr Function

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Hi,In SQL SERVER 2005 Database I have a field called MedNames with values such as "sodium % 34ml" "desx chloride 9 % 76ml"I need to return the words before and including % so "sodium % 34ml"  should return ""sodium % " Is it possible to do it in a select statement? I need to populate a dropdownlist with the shortened names.Thanks

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In VB there is InStr, in Excel you have SEARCH. what function can i use to search a string for a specific string. ie: how can i find where a space is in someones name?

our database has a table that is used for security. it contains a user code, user name and passcode. i need to split the username (currently forename and surname in same field) into two, around the space.

in VB i would write something like
strFName = left(<usernamefield>,InStr(1,<usernamefield>," ")-1)
to get the forename and similar to get the surname. how can i do this in SQL so that a view will supply the data apprpriately?

one of the reasons i want to do this is so that i can sort the users by surname! another is so that i can give options on their usercode - a combination of forename initial and 2 characters from surname.

any help welcomed.

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Jul 20, 2005

Hi everybody,I was looking for an equivalent ORACLE INSTR Function in MSSQL but Idont found it and I dont know if it exist so I must to write it andthis is the code. Maybe it will be helful to you:/************************************************** *************************Description:Looks for a string inside another string and returns an integerthat correspond to the position of first ocurrence.Parameters:Input:- strSource. Contains the string where the functions look for theother string- strToFind. Contains the string to look for inside strSourceSalida:- Integer value indicating the position of first occurrence ofstrToFind in strSource************************************************** *************************/CREATE FUNCTION posSubString(@strSource varchar(400),@strToFind varchar(200)) RETURNS intASBEGINDECLARE@position int,@maxPos int,@longSubStr int,@res int,@strSub varchar(200)SET @position = 0SET @res = 0SET @longSubStr = LEN(RTIRM(LTRIM(@strToFind)))SET @maxPos = LEN(@strSource) - @longSubStrWHILE (@position <= @strToFind)BEGINSET @strSub = SUBSTRING(@strSource, @position, @longSubStr)IF (@strToFind = @StrSub)BEGINSET @res = @position - 1RETURN @resENDELSESET @position = @position + 1ENDRETURN @resENDAlonso

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Sep 25, 2000

My question is about the INSTR function of MSAccess
I want to know

Goodbye at every
I would you like to know if in TransactSQL of SQLServer7 exist a function that return the position of a string into an other string .
that is a Instr function MSAccess like


I'm sorry for my bad English
Thank you for everything


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I went to Microsoft to find some info about the function Instr. I need to
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anyone explain to me Microsoft's example?? I am little confused by the
parameters used and the explanation it gives back to me??

Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP" ' String to search in.
SearchChar = "P" ' Search for "P".
MyPos = Instr(4, SearchString, SearchChar, 1) ' A textual comparison
starting at position 4. Returns 6.
MyPos = Instr(1, SearchString, SearchChar, 0) ' A binary comparison
starting at position 1. Returns 9.
MyPos = Instr(SearchString, SearchChar) ' Comparison is binary by default
(last argument is omitted). Returns 9.
MyPos = Instr(1, SearchString, "W") ' A binary comparison starting at
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My problem is this:

I need to scan within SearchString for blanks/spaces characters. When I
find one, then place the values to the left and right of it in seperate
columns. For example, I would need to scan 'John Smith A' and then place
'John' in FirstName column, 'Smith' in LastName column, and 'A' in MidName

I think this is how my code would read, but I am confused on how to place
the results into my table to the correct columns?

my search string would be SearchString = 'John Smith A'
my SearchChar would be SearchChar = ' ' (note I am searching for a
space/blank character)

So would then my code be like:

Dim SearchString, SearchChar, MyPos
SearchString = 'John Smith A'
SearchChar = ' '
MyPos = Instr(1, SearchString, SearchChar, 0)

How do I get whatever is returned from the Instr function to a column in a

Any help would be great.


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Hi All

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Here are some examples of what the column data looks like: (found in the [csMethod] column


I made a define table which lists an ID (primary key) and instr to search for as well as the full browser name. (define.browser)


1___Opera+7_______Opera 7
2___Opera/9_______Opera 9
4___Firefox/1.0___Mozilla Firefox 1.0
5___Firefox/1.5___Mozilla Firefox 1.5
6___Firefox/2.0___Mozilla Firefox 2.0
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9___MSIE+6________Microsoft Internet Explorer 6
10___MSIE+7________Microsoft Internet Explorer 7
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Greetings All

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thanks as always


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The syntax for Oracle's INSTR function is

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string1 is the string to search.

string2 is the substring to search for in string1.

start_position is the position in string1 where the search will start. This argument is optional. If omitted, it defaults to 1. The first position in the string is 1. If the start_position is negative, the function counts back start_position number of characters from the end of string1 and then searches towards the beginning of string1.

nth_appearance is the nth appearance of string2. This is optional. If omiited, it defaults to 1.

In SQL Server, we are having CHARINDEX and PATINDEX functions. But they will not accept the fourth paremeter (nth_appearance)

Do anybody know the solution for this ????

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Hello All -

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