until recently ive been using a rank equation to calculate rank,
essentially doing a select statement and selecting this as the rank field, where query 2 is the same as query 1:
((select count(*) from (query1) where (query1).value < (query2).value) +1)) as Rank
problem is that this is now running like a dog (takes 10 secs) and i'd like to try and do this another way- 2005 has a rank function, how can i do this in 2000?
here is the full statement :
SELECT StudentId, GCSE_Score, LTRIM(STR
((SELECT COUNT(*)
FROM dbo.[Score2004-05]
WHERE GCSE_score < s.GCSE_Score) + 1)) AS GCSE_Rank, SetId
FROM dbo.[Score2004-05] S
WHERE (SetId = '2004/2005')
This is a working 12 month intrest equation. I used this for the layout section but I am trying to take this and it gives me the correct values. But what I need to do next is have it sum those values.
I tried =SUM( whole expression but that didnt work) you can laugh at me I know but any help would be great!
=Switch(Fields!eqprecdt.Value< CDate("1 Jan 2007"),Fields!bookvalue.Value*datediff("d",Now(),#1/1/2007#)* .07/365,Fields!eqprecdt.Value> CDate("1 Jan 2007"), Fields!bookvalue.Value * datediff("d",Now(),Fields!eqprecdt.Value)* .07/365)*-1
I am not sure if I am posting this is the right place, please let me know if a better place exists.I am trying to figure out the distance from a point on the earth to a route between two other points. All points that I have are in latitude and longitude secondsIE: 51-52-40.6700N => 186760.6700NI am able to find the distance between two points on the globe using a custom function FindDist(latitude1, longitude1, latitude2, longitude2)I did the legwork for the math and was able to come up with this psudo code: p1 = start of routep2 = end of routep3 = point of referencep4 = INTERSECT(LINE(p1,p2), PERPENDICULAR_LINE(p1,p2,p3)) The direct distance between p4 and p3 is somewhere in the range of 0 - 70 and encompasses all points in the US (We only deal in the US) which is incorrect. If I do the conversion of p4 to latitude and longitude I get numbers that start out at 1000 which is also incorrect.I am doing the conversion with the following: DECLARE @lat2 VARCHAR(25)SET @lat2 = (@p4x * 3600)IF @p4x < 0BEGINSET @lat2 = @lat2 + 'S' ENDIF @p4x > 0BEGINSET @lat2 = @lat2 + 'N' ENDDECLARE @lng2 VARCHAR(25)SET @lng2 = @p4y * 3600IF @p4y < 0BEGINSET @lng2 = @lng2 + 'W' ENDIF @p4y > 0BEGINSET @lng2 = @lng2 + 'E' END I am not sure, however, how to either:a) find the latitude / longitude of p4b) find the distance in miles between p3 and p4Either of these will solve my problemI know this is a rather odd question, but if anyone can help me that would be great. If you need more information, let me know and I will try and explain things further.
In AS 2008 it is possible to build time series model using ARIMA algorithm. But how exactly the ARIMA model eqation can be interpreted? For example, I have the following ARIMA equation in the mining legend of the (only) node: ARIMA equation: ARIMA ({1,1.06331498820371E-02,-9.1320555134096E-04,6.82290767622866E-03,5.16804012070969E-02,5.33387901298971E-02,7.27630334027759E-04,-4.08433722450516E-02},1,{1,0.637381531245194}) X ({1,8.85242031097984E-02},0,{1,3.46939494788227E-02})(26) X ({1},1,{1,-0.94291566648386})(13) Intercept:706.18948950439
I am used to the notations like ARIMA(Autoregressive order, Order of differencing, Moving average order). So, I can guess, that term like {1,1.06331498820371E-02,-9.1320555134096E-04,6.82290767622866E-03,5.16804012070969E-02,5.33387901298971E-02,7.27630334027759E-04,-4.08433722450516E-02} expresses coefficients in either autoregressive or moving average terms. But how can I interpret patterns followed by X like ARIMA(...)X(...)X(...)? Do they express periodical patterns? If so, how can I pick periods from this equation?
How to get the CASE results highlighted in BOLD into this equation; "(LogOut - LogIn) + (LunchBreak) -(AMBreak) + (PMBreak) AS TimeWorked" ? Thank you. CREATE VIEW dbo.vwu_ReportViewASSELECT EmployeeID , LastName , FirstName , LocationCode , UserID , Today , Login , AMBreakOut , AMBreakIn , CASE WHEN ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) >= 0 AND ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) <= 19 THEN '0' WHEN ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) >= 20 AND ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) <= 34 THEN '15' WHEN ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) >= 35 AND ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) <= 49 THEN '30' WHEN ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) > = 50 AND ISNULL(DATEDIFF(Minute, AMBreakOut, AMBreakIn),0) <= 64 THEN '45' ELSE '60' END AS AMBreak , LunchOut , LunchIn , CASE WHEN ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) >= 0 AND ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) <= 66 THEN '0' WHEN ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) >= 67 AND ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) <= 81 THEN '15' WHEN ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) >= 82 AND ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) <= 96 THEN '30' WHEN ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) >= 97 AND ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) <= 111 THEN '45' WHEN ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) >= 112 AND ISNULL(DATEDIFF(Minute, LunchOut, LunchIn),0) <= 126 THEN '60' ELSE '75' END AS LunchBreak, PMBreakOut , PMBreakIn , CASE WHEN ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) >= 0 AND ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) <= 19 THEN '0' WHEN ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) >= 20 AND ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) <= 34 THEN '15' WHEN ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) >= 35 AND ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) <= 49 THEN '30' WHEN ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) >= 50 AND ISNULL(DATEDIFF(Minute, PMBreakOut, PMBreakIn),0) <= 64 THEN '45' ELSE '60' END AS PMBreak , Logout , Comments , LoginLogon , AMBreakOutLogon , AMBreakInLogon , LunchOutLogon , LunchInLogon , PMBreakOutLogon , PMBreakInLogon , LogoutLogon ,(LogOut - LogIn) + (LunchBreak) -(AMBreak) + (PMBreak) AS TimeWorked
ARIMA ({1,-6.88479117532726E-02,-0.41430691637436},0,{1,4.42986549117398E-03}) X ({1,-0.473450289323228},0,{1,0.013772719862356,-2.14724317829266E-02,-4.80711350511344E-02,-1.15173259713497E-02,-9.86142925337024E-03,1.06803677786174})(6) Intercept:18561.1721123981
I do understand the coefficients part and the seasonal part as well, however, I have trouble deciphering what exactly is the intercept here. Initially, I thought it would be equivalent to the value of mu in the original Box-Jenkins equation (so indicate a level), then I thought it's an intercept for the AR terms. It seems that none of these interpretations is good. The only official explanation I found at msdn was:
"Normally, the intercept (VALUETYPE = 11) or residual in a regression equation tells you the value of the predictable attribute, at the point where the input attribute, is 0. In many cases, this might not happen, and could lead to counterintuitive results.
For example, in a model that predicts income based on age, it is useless to learn the income at age 0. In real-life, it is typically more useful to know about the behavior of the line with respect to average values. Therefore, SQL Server Analysis Services modifies the intercept to express each regressor in a relationship with the mean.
This adjustment is difficult to see in the mining model content, but is apparent if you view the completed equation in the Mining Legend of the Microsoft Tree Viewer. The regression formula is shifted away from the 0 point to the point that represents the mean. This presents a view that is more intuitive given the current data.Therefore, assuming that the mean age is around 45, the intercept (VALUETYPE = 11) for the regression formula tells you the mean income.
SELECT[RANK] ,[KEY],idc.* FROMFREETEXTTABL (dbo.indice,mcaNombre,fabNombre,catNombre), 'ropa adidas nike', LANGUAGE 3082, 5) res left join dbo.indice idc with (nolock) on idc.idcCodigo=res.[key] ORDER BY [RANK] DESC;
Result:
RANK KEY 182 03 04 01
Why idcCods's 1 and 2 have different rank?? because idcCod's 3 and 4 affects ?? or it's just thinks of language??
Ok. Im not able to understand this logic please help. As you can see we have 2 columns of ranks, 1)normal 2)corrective. what is the logic behind this and how do u write a query for this? these ranks are for the Salary Column. Imran, "You truly do not know someone untill you fight them."-THE MATRIX.
EmpID Empname EmpSalary RankNormal RankCorrective 1 A 150001 1 2 B 100002 4 3 C 150001 1 4 D 40003 5 5 E 150001 1 6 F 15004 6 7 G 15004 6 8 H 5005 8
Hi All, Please let me know the equivalent of RANK() over ( order by...) in SQL server 2000. I thought this was supported in SQL server 2000. Please let me know if there exists a user defined function. Thanks in Advance.
I would like to write a query that gives me the values of a set ofobservations, and their rank.CREATE TABLE #Values(val int)INSERT #Values SELECT 1INSERT #Values SELECT 5INSERT #Values SELECT 10I would like to select this:1 10 -- rank 1, value 102 53 1I can put them into a temp table with an identity column, ordered bythe column I'm interested in, and then retrieve in order by theidentity column. I'm wondering if there's a way to do that with asubquery.Thanks,Jim
I've written a bunch of code using contains for fts. Then as I was trying to run the sorting, I realized that I have to use containstable in order to sort by rank. Is that correct? When I was using contains, I just used it as a where clause so I would have something like...
WHERE ((PostedUntil >= '5/22/2006') AND (SiteId=199)) AND (CONTAINS (PositionTitle, '"sales"') OR CONTAINS (Description, '"sales"'))
From the examples I've seen, in order to use containstable, I have to join a new dynamic table to the freetext enabled table and it only uses 1 containstable phrase for the new table. In my case, I may have multiple containstable phrases, so would they all fall in a () set like..
FROM Categories AS FT_TBL INNER JOIN (CONTAINSTABLE (table, col1, searchphrase) OR (CONTAINSTABLE(table, col2, searchphrase2) OR CONTAINSTABLE (table, col3, searchphrase3)) AS KEY_TBL
... or would each containstable have to be a new join? I don't want to spend anymore time going back and rewriting code just to test it since it's about a days worth of recoding. Thanks.
ive created a photo sharing site, and im trying to show the statisics for certain users, so far i can COUNT all the photos the user has upload, and show them in descending order, but i need to be able to see the ranking of the user, like :
I need help in understanding how the rank is calculated in FREETEXTABLE. I have a following query
select ft_tbl.saon ,ft_tbl.paon ,ft_tbl.street ,ft_tbl.postcode ,key_tbl.rank from temp as ft_tbl INNER JOIN freetextTABLE(temp, (saon, paon, street), '80 ridge avenue', 15) as key_tbl ON FT_tbl.ID = key_tbl.[key]
First, the resulting rows does have one record which has an address 80 ridge avenue but it appears at 15th place. Ideally it should appear on 1st. All the ranks of the results are same.
Second, the results are also showing two rows which does not contain the specified search string at all. They not only appears above in the resulting table but also have the same rank as the result in question (80 ridge avenue). For example result shows €œLong Ridges, Flat 21, Fortis Green€? at fifth place which is no way near the search string. And actual record shows up at 15th Place
Is there any way we can influence the rank to show exact match first. Just to clarify I have removed the digits from noise file as we need to search house numbers. Digits appears in noise file as default.
I have a report created and within the report is columns that perform additions on the fields from the database.
I want to create a rank column to show the rank of the row compare with the rest.
Col1 Col2 Total Ranks 1 2 3 3 2 3 5 1 2 2 4 2
On the above Col 1 and 2 would come form my database, Total is calculated by the report. How can I get ranking on this total? I cannot sort by the total as the report should only showing rankings but not be ordered by the rank.
I am using SQL Server 2005 Reporting Services...anny help is much appreciated.
(SELECT JumpHeight, DogIdent, MIN(RunDate) as "MinRunDate", COUNT(Event_ID) AS "NoEvents",
RANK() OVER (PARTITION BY JumpHeight ORDER BY COUNT(Event_ID) DESC, MIN(RunDate)) AS "HeightRank"
FROM EventData
WHERE Event=@Event
GROUP BY JumpHeight, DogIdent) AS xx, Dogs, DogOwner
WHERE (Dogs.Breed = @Breed AND xx.DogIdent = Dogs.DogIdent and Dogs.Owner_ID = DogOwner.Owner_ID) AND
(xx.HeightRank <= 10)
ORDER BY xx.JumpHeight, xx.HeightRank
produces this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
3
1
2/19/2006
Some Owner
Otto
08
4
1
3/12/2006
Some Owner
Schotzie
I want it to produce this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
1
1
2/19/2006
Some Owner
Otto
08
2
1
3/12/2006
Some Owner
Schotzie
I have tried several things and cannot correct the problem. Obviously, RANK is being evaluated in the wrong place, but placing it elsewhere has failed to produce the above results.
Hi,All, I have one table like this UserID,Name,GameScore 1 A 25 2 B 23 3 C 22 4 D 25 5 E 23 6 F 26 Now i want the query which return like this Name Score Rank F 26 1 A 25 2 D 25 2 B 23 3 E 23 3 C 22 4 Can anyone give me the sql 2000 query for this
In the Sql below, sample from William Pearson, the amount Spend is in descending order and the Rank number is in ascending order. Like this:
Spend Rank 24 1 12 2 10 3 9 4
What I wish to accomplish is:
Spend Rank (descending) 24 4 12 3 10 2 9 1
Please let me know what I need to accomplish it.
Thanks for the help
Victor
SELECT CompanyName, Spend, (SELECT COUNT(*) FROM ACC0704 AS CoSpendTotal WHERE ACC0704.Spend <= CoSpendTotal.Spend) AS Rank FROM ACC0704 ORDER BY Spend DESC
i want to create a report so that a list of the top 30 records are returned to the report user. In the report i want to have the records position in the list shown (ie the first row should have 1. and the second should be 2. right on down to the 30th having 30.)
i am trying to create a rank formula.i just need to return the highest MCC count for the mcc code and return the seller code...So eg row 3 and 4, there are two MMC CODE called 4772, i need the formula to return the seller code r10, this is because r10 has 9 counts against that mcc code, and r03 has 9,
WITH MEMBER [Measures].[Rank] AS 'Rank ( Product.CurrentMember,Order( {Product.CurrentMember.Parent.Children} ,[Profit], DESC) ) ' SELECT {[Profit] , [Rank]} ON COLUMNS, Drink.Children ON ROWS FROM Sales
I need to get the previous price for all my PROMOTION records but not when the previous record is a type PROMOTION also it needs to keep going back to get the price.
I have created a table with RANK in which works OK to get previous price for all but how can I say if previous price is type PROMOTION go to next previous prices...
Bets way to show an example is with a jpeg image I have but having trouble inserting into this message...
SELECT a.[StartPrice] ,a.[ProductID] ,a.[Colour] ,ISNULL(b.[Price],a.[Price]) AS [Price Before] ,a.[Price] AS [Promotion Price]
I am trying to return the 100th ranking in my SQL, ie
SELECT DailyValueChange, BUSINESS_DATE, RANK() OVER (order by DailyValueChange) AS RANK_Vals
FROM Table
WHERE (BUSINESS_DATE = @CurrentBusDate) AND (RANK_Vals = 100)
However when I try to update the Stored Procedure it tells me RANK_Vals is an invalid column name, which is not the case as if I run it without the Where clase it runs and returns all results.
Any advice on how to get around this would be greatly appreciated.
Hi - Can someone point me to a single document that tells me how to get started from nothing with SQL Server 2005 Express? I keep getting pointed to lists of many documents, none of which does what I specifically need. They all seem to have many general instructions, but I just want to get started with some simple database that I load with a bit of data and then perform some queries.
I have ordered a book from Amazon but don't have much hope that it will do what I need.
I have a table that has the definition from the picture. Let's suppose I will sort the list based on last column (DATA.ORA - DESC). That means the last row inserted is the first one in the sorted list.
What I would like to do is to get only the records when the value of a specific column is different from the row below.
For instance I would like to get the rows where the column WHITE has different values. When the status for column WHITE changes from 0 to 1 or from 1 to 2 etc., then I need that row no matter if next 5 rows has the same status (1).
In the picture you see what the result of query should be:
Result: only the lines where the value of column WHITE is different than the row below.
Given the following results: col0 col1 col2 THY 2,265,850 31 VIE 1,474,994 20 RID 1,221,800 17 ACC 1,124,335 15 FEI 445,184 6 DIR 433,783 6 ROM 324,365 4
What is the best way in a query to get the rank of the returned rows by either col1 or col2. In other words who's the number 1,2,3 etc...
total count col0 = 7 total col1 = 7,290,310 total col2 (would eqaul 100%)= 99%
Looking for a mathmatical solution to this any help would be appreciated.
Guys Spent all morning on this - hope someone can help I've got some select code :
declare @BusinessDate DATETIME set @BusinessDate = '28 Feb 2005'
select --?? as period tdbe.eventid , tdbe.tradeid ,tdbe.cashflowstartdate from HDD_t_HA HA join hdd_t_Hedge_Instrument HI on HA.HAId = HI.HAId join hdd_t_TDB_Event TDBE on HI.EventId = TDBE.EventId join hdd_t_TDB TDB on TDBE.TradeId = TDB.TradeId where ha.haid = 29 and ha.validfrom <= getdate() and ha.validto > getdate() and tdbe.effectivefrom <= @BusinessDate and tdbe.effectiveto > @BusinessDate and tdb.effectivefrom <= @BusinessDate and tdb.effectiveto > @BusinessDate --and tdbe.tradeid = 117 order by tdbe.tradeid , cashflowstartdate
I'm trying to derive a 'period' value which is an integer based on the ordering of cashflowstartdatefor each tradeid group. The desired effect is as below
Assuming that I have a table similar to this simplified version:
CREATE TABLE [SomeTable] ([Field1] NVARCHAR(50));
How could I count and rank the instances of specific values in the "field1" column? For example, let's say that I want to show the frequency of the column values like so:
field1 count some value 24 another word 20 a value 5
I'm fairly new to SQL and I have been asked to load multiple tables with duplicate and inconsistent data into a single table. Each source (table) has been assigned a rank in terms of the quality and reliability. After some thought, I have come up with this solution to get all of the data loaded based on rank.
Does anyone know of a better way to do this?
Value is a unique key.
SELECT * FROM table_1
union
SELECT * FROM table_2 where (value + '_' + yr) in ( select value + '_' + yr from table_2 except select value + '_' + yr from table_1)
union
SELECT * FROM table_3 where (value + '_' + yr) in ( select value + '_' + yr from table_3 except select value + '_' + yr from table_2 except select value + '_' + yr from table_1)
