I am trying to return the 100th ranking in my SQL, ie
SELECT DailyValueChange, BUSINESS_DATE, RANK() OVER (order by DailyValueChange) AS RANK_Vals
FROM Table
WHERE (BUSINESS_DATE = @CurrentBusDate) AND (RANK_Vals = 100)
However when I try to update the Stored Procedure it tells me RANK_Vals is an invalid column name, which is not the case as if I run it without the Where clase it runs and returns all results.
Any advice on how to get around this would be greatly appreciated.
i want to create a report so that a list of the top 30 records are returned to the report user. In the report i want to have the records position in the list shown (ie the first row should have 1. and the second should be 2. right on down to the 30th having 30.)
Hi,I am using MS SQL server 2005 and wondering how to sort my results by rank using FREETEXT on multiple columns. Is there a way to do this? My two colums are:title and description
ON dbo.Track_ID.SM_ID = dbo.transactions.sm_session_id
GROUP BY dbo.Track_ID.TrackID
)
) Once moved to SQL Server 2005 the statement would not return and showed SOS_SCHEDULER_YIELD to be the waittype when executed. This machine is SP1 and needs to be upgraded to SP2, something that is not going to happen near time.
I changed the SQL to the following, SQL Server now runs it in under a second, but now the app is not functioning correctly. Are the above and the following semantically the same?
UPDATE dbo.Track_ID
SET dbo.Track_ID.Processed = 4 --Regular 1 leg call thats been completed
Consider this SQL:SELECT my_field FROM my_table WHERE my_field IN ('value2', 'value1','value3')Simple enough, but is there anyway to specify that the result should beordered exactly like the "IN" clause states? So when this recordsetcomes back, I want it like this:my_field------------value2value1value3Possible?Deane
My source table has two columns... Policynum and PolicyStartdate and data looks like.. . Policynum             PolicyStartdate 123G                      01/01/2012    456D                      02/16/2012     789A                      01/21/2012 163J                      05/25/2012
Now my output should return based on 3 parameters..
First two parameters are date range... let say @fromdt and @todt
Third parameter is @policynum
Scenario-1: Enter dates in date range param and leave policynum param blank Ex: policystartdate between '01/01/2012 and '01/31/2012'.... It returns 1st and 3rd rows from above in the output
Scenario-2: enter policy num in policynum param and don't select any dates Ex:Â policynum ='456D'Â Â Â Â It returns 2nd row in the output
Scenario-3: Select dates in date range param and enter policynum in param Ex: policystartdate between '01/01/2012 and '01/31/2012' and policynum ='163J'. it should return only 4th row even though dates were selected(Override date range when policynum is entered in param and just return specified policynum row in the output)
Hi! Has anyone experienced this problem? Certain queries that work fine in SQL 6.5 and Oracle return inconsistent / inaccurate results in SQL 7 (with SP1). These queries include an IN clause with a range of values. For example, the following query: SELECT columnA, columnB, columnC, columnD FROM table WHERE columnD = 'I' AND columnA IN (1,2,3,11,19) go
returns a different result than this query: SELECT columnA, columnB, columnC, columnD FROM table WHERE columnD = 'I' AND columnA IN (1,3,11,2,19) go
The only way we have stumbled upon to get accurate results consistently is to order the range values from largest to smallest: AND columnA IN (19,11,3,2,1)
Have not seen this documented anywhere. We are in the process of re-ordering these ranges in our code, but I welcome any ideas or comments... Thanks!
I'm trying to create a WHERE clause that will have different results depending on a parameter that is entered. For example, if you put in a number, it will only calculate the rows where the column ID matches that number. However, if you put in 0, which doesn't exist in that column ID, it will instead calculate all the data in the table.
So the below would be a very basic idea of what I'm trying to do, but I'm not sure how to do it with proper syntax.
I am fairly new with SQL and still learning. I have used a case statemtent for a column in my select list and want to use the results of that statement's field in my WHERE clause but it is not working for me. Here is the code I have so far:
SELECT l.loanid, p.investorid, l.duedate, case when pc.duedate >= l.duedate then pc.duedate end as RateDueDate, pc.interestrate FROM loan l inner join participation p on p.loanid = l.loanid inner join paymentchange pc on pc.loanid = l.loanid where p.investorid = '12345' and RateDueDate is not null order by l.loanid, pc.duedate
I want to put the results of this case statment in my where clause like highlighted above but it is not working because RateDueDate is not an actual column in the table. Any help would be greatly appreciated.
SELECT[RANK] ,[KEY],idc.* FROMFREETEXTTABL (dbo.indice,mcaNombre,fabNombre,catNombre), 'ropa adidas nike', LANGUAGE 3082, 5) res left join dbo.indice idc with (nolock) on idc.idcCodigo=res.[key] ORDER BY [RANK] DESC;
Result:
RANK KEY 182 03 04 01
Why idcCods's 1 and 2 have different rank?? because idcCod's 3 and 4 affects ?? or it's just thinks of language??
Ok. Im not able to understand this logic please help. As you can see we have 2 columns of ranks, 1)normal 2)corrective. what is the logic behind this and how do u write a query for this? these ranks are for the Salary Column. Imran, "You truly do not know someone untill you fight them."-THE MATRIX.
EmpID Empname EmpSalary RankNormal RankCorrective 1 A 150001 1 2 B 100002 4 3 C 150001 1 4 D 40003 5 5 E 150001 1 6 F 15004 6 7 G 15004 6 8 H 5005 8
Hi All, Please let me know the equivalent of RANK() over ( order by...) in SQL server 2000. I thought this was supported in SQL server 2000. Please let me know if there exists a user defined function. Thanks in Advance.
I would like to write a query that gives me the values of a set ofobservations, and their rank.CREATE TABLE #Values(val int)INSERT #Values SELECT 1INSERT #Values SELECT 5INSERT #Values SELECT 10I would like to select this:1 10 -- rank 1, value 102 53 1I can put them into a temp table with an identity column, ordered bythe column I'm interested in, and then retrieve in order by theidentity column. I'm wondering if there's a way to do that with asubquery.Thanks,Jim
I've written a bunch of code using contains for fts. Then as I was trying to run the sorting, I realized that I have to use containstable in order to sort by rank. Is that correct? When I was using contains, I just used it as a where clause so I would have something like...
WHERE ((PostedUntil >= '5/22/2006') AND (SiteId=199)) AND (CONTAINS (PositionTitle, '"sales"') OR CONTAINS (Description, '"sales"'))
From the examples I've seen, in order to use containstable, I have to join a new dynamic table to the freetext enabled table and it only uses 1 containstable phrase for the new table. In my case, I may have multiple containstable phrases, so would they all fall in a () set like..
FROM Categories AS FT_TBL INNER JOIN (CONTAINSTABLE (table, col1, searchphrase) OR (CONTAINSTABLE(table, col2, searchphrase2) OR CONTAINSTABLE (table, col3, searchphrase3)) AS KEY_TBL
... or would each containstable have to be a new join? I don't want to spend anymore time going back and rewriting code just to test it since it's about a days worth of recoding. Thanks.
ive created a photo sharing site, and im trying to show the statisics for certain users, so far i can COUNT all the photos the user has upload, and show them in descending order, but i need to be able to see the ranking of the user, like :
until recently ive been using a rank equation to calculate rank,
essentially doing a select statement and selecting this as the rank field, where query 2 is the same as query 1:
((select count(*) from (query1) where (query1).value < (query2).value) +1)) as Rank
problem is that this is now running like a dog (takes 10 secs) and i'd like to try and do this another way- 2005 has a rank function, how can i do this in 2000?
here is the full statement :
SELECT StudentId, GCSE_Score, LTRIM(STR ((SELECT COUNT(*) FROM dbo.[Score2004-05] WHERE GCSE_score < s.GCSE_Score) + 1)) AS GCSE_Rank, SetId FROM dbo.[Score2004-05] S WHERE (SetId = '2004/2005')
I need help in understanding how the rank is calculated in FREETEXTABLE. I have a following query
select ft_tbl.saon ,ft_tbl.paon ,ft_tbl.street ,ft_tbl.postcode ,key_tbl.rank from temp as ft_tbl INNER JOIN freetextTABLE(temp, (saon, paon, street), '80 ridge avenue', 15) as key_tbl ON FT_tbl.ID = key_tbl.[key]
First, the resulting rows does have one record which has an address 80 ridge avenue but it appears at 15th place. Ideally it should appear on 1st. All the ranks of the results are same.
Second, the results are also showing two rows which does not contain the specified search string at all. They not only appears above in the resulting table but also have the same rank as the result in question (80 ridge avenue). For example result shows €œLong Ridges, Flat 21, Fortis Green€? at fifth place which is no way near the search string. And actual record shows up at 15th Place
Is there any way we can influence the rank to show exact match first. Just to clarify I have removed the digits from noise file as we need to search house numbers. Digits appears in noise file as default.
I have a report created and within the report is columns that perform additions on the fields from the database.
I want to create a rank column to show the rank of the row compare with the rest.
Col1 Col2 Total Ranks 1 2 3 3 2 3 5 1 2 2 4 2
On the above Col 1 and 2 would come form my database, Total is calculated by the report. How can I get ranking on this total? I cannot sort by the total as the report should only showing rankings but not be ordered by the rank.
I am using SQL Server 2005 Reporting Services...anny help is much appreciated.
(SELECT JumpHeight, DogIdent, MIN(RunDate) as "MinRunDate", COUNT(Event_ID) AS "NoEvents",
RANK() OVER (PARTITION BY JumpHeight ORDER BY COUNT(Event_ID) DESC, MIN(RunDate)) AS "HeightRank"
FROM EventData
WHERE Event=@Event
GROUP BY JumpHeight, DogIdent) AS xx, Dogs, DogOwner
WHERE (Dogs.Breed = @Breed AND xx.DogIdent = Dogs.DogIdent and Dogs.Owner_ID = DogOwner.Owner_ID) AND
(xx.HeightRank <= 10)
ORDER BY xx.JumpHeight, xx.HeightRank
produces this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
3
1
2/19/2006
Some Owner
Otto
08
4
1
3/12/2006
Some Owner
Schotzie
I want it to produce this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
1
1
2/19/2006
Some Owner
Otto
08
2
1
3/12/2006
Some Owner
Schotzie
I have tried several things and cannot correct the problem. Obviously, RANK is being evaluated in the wrong place, but placing it elsewhere has failed to produce the above results.
Hi,All, I have one table like this UserID,Name,GameScore 1 A 25 2 B 23 3 C 22 4 D 25 5 E 23 6 F 26 Now i want the query which return like this Name Score Rank F 26 1 A 25 2 D 25 2 B 23 3 E 23 3 C 22 4 Can anyone give me the sql 2000 query for this
In the Sql below, sample from William Pearson, the amount Spend is in descending order and the Rank number is in ascending order. Like this:
Spend Rank 24 1 12 2 10 3 9 4
What I wish to accomplish is:
Spend Rank (descending) 24 4 12 3 10 2 9 1
Please let me know what I need to accomplish it.
Thanks for the help
Victor
SELECT CompanyName, Spend, (SELECT COUNT(*) FROM ACC0704 AS CoSpendTotal WHERE ACC0704.Spend <= CoSpendTotal.Spend) AS Rank FROM ACC0704 ORDER BY Spend DESC
i am trying to create a rank formula.i just need to return the highest MCC count for the mcc code and return the seller code...So eg row 3 and 4, there are two MMC CODE called 4772, i need the formula to return the seller code r10, this is because r10 has 9 counts against that mcc code, and r03 has 9,
WITH MEMBER [Measures].[Rank] AS 'Rank ( Product.CurrentMember,Order( {Product.CurrentMember.Parent.Children} ,[Profit], DESC) ) ' SELECT {[Profit] , [Rank]} ON COLUMNS, Drink.Children ON ROWS FROM Sales
I need to get the previous price for all my PROMOTION records but not when the previous record is a type PROMOTION also it needs to keep going back to get the price.
I have created a table with RANK in which works OK to get previous price for all but how can I say if previous price is type PROMOTION go to next previous prices...
Bets way to show an example is with a jpeg image I have but having trouble inserting into this message...
SELECT a.[StartPrice] ,a.[ProductID] ,a.[Colour] ,ISNULL(b.[Price],a.[Price]) AS [Price Before] ,a.[Price] AS [Promotion Price]
Hi - Can someone point me to a single document that tells me how to get started from nothing with SQL Server 2005 Express? I keep getting pointed to lists of many documents, none of which does what I specifically need. They all seem to have many general instructions, but I just want to get started with some simple database that I load with a bit of data and then perform some queries.
I have ordered a book from Amazon but don't have much hope that it will do what I need.
I have a table that has the definition from the picture. Let's suppose I will sort the list based on last column (DATA.ORA - DESC). That means the last row inserted is the first one in the sorted list.
What I would like to do is to get only the records when the value of a specific column is different from the row below.
For instance I would like to get the rows where the column WHITE has different values. When the status for column WHITE changes from 0 to 1 or from 1 to 2 etc., then I need that row no matter if next 5 rows has the same status (1).
In the picture you see what the result of query should be:
Result: only the lines where the value of column WHITE is different than the row below.
Given the following results: col0 col1 col2 THY 2,265,850 31 VIE 1,474,994 20 RID 1,221,800 17 ACC 1,124,335 15 FEI 445,184 6 DIR 433,783 6 ROM 324,365 4
What is the best way in a query to get the rank of the returned rows by either col1 or col2. In other words who's the number 1,2,3 etc...
total count col0 = 7 total col1 = 7,290,310 total col2 (would eqaul 100%)= 99%
Looking for a mathmatical solution to this any help would be appreciated.