Select List Contains More Items Than Insert List

Mar 21, 2008

I have a select list of fields that I need to select to get the results I need, however, I would like to insert only a chosen few of these fields into a table. I am getting the error, "The select list for the INSERT statement contains more items than the insert list. The number of SELECT values must match the number of INSERT columns."
How can I do this?

Insert Query:
insert into tsi_payments (PPID, PTICKETNUM, PLINENUM, PAMOUNT, PPATPAY, PDEPOSITDATE, PENTRYDATE, PHCPCCODE)
SELECT DISTINCT
tri_IDENT.IDA AS PPID,
tri_Ldg_Tran.CLM_ID AS PTicketNum,
tri_ClaimChg.Line_No AS PLineNum,
tri_Ldg_Tran.Tran_Amount AS PAmount,

CASE WHEN tln_PaymentTypeMappings.PTMMarsPaymentTypeCode = 'PATPMT'
THEN tri_ldg_tran.tran_amount * tln_PaymentTypeMappings.PTMMultiplier
ELSE 0 END AS PPatPay,

tri_Ldg_Tran.Create_Date AS PDepositDate,
tri_Ldg_Tran.Tran_Date AS PEntryDate,
tri_ClaimChg.Hsp_Code AS PHCPCCode,
tri_Ldg_Tran.Adj_Type,
tri_Ldg_Tran.PRS_ID,
tri_Ldg_Tran.Create_Time,
tri_Ldg_Tran.Adj_Group,
tri_Ldg_Tran.Payer_ID,
tri_Ldg_Tran.TRN_ID,
tri_ClaimChg.Primary_Claim,
tri_IDENT.Version
FROM [AO2AO2].MARS_SYS.DBO.tln_PaymentTypeMappings tln_PaymentTypeMappings RIGHT OUTER JOIN
qs_new_pmt_type ON tln_PaymentTypeMappings.PTMClientPaymentDesc =
qs_new_pmt_type.New_Pmt_Type RIGHT OUTER JOIN
tri_Ldg_Tran RIGHT OUTER JOIN
tri_IDENT LEFT OUTER JOIN
tri_ClaimChg ON tri_IDENT.Pat_Id1 =
tri_ClaimChg.Pat_ID1 ON tri_Ldg_Tran.PRS_ID =
tri_ClaimChg.PRS_ID AND
tri_Ldg_Tran.Chg_TRN_ID =
tri_ClaimChg.Chg_TRN_ID
AND tri_Ldg_Tran.Pat_ID1 = tri_IDENT.Pat_Id1 LEFT OUTER JOIN
tri_Payer ON tri_Ldg_Tran.Payer_ID
= tri_Payer.Payer_ID ON qs_new_pmt_type.Pay_Type
= tri_Ldg_Tran.Pay_Type AND
qs_new_pmt_type.Tran_Type = tri_Ldg_Tran.Tran_Type
WHERE (tln_PaymentTypeMappings.PTMMarsPaymentTypeCode <> N'Chg')
AND (tln_PaymentTypeMappings.PTMClientCode = 'SR')
AND (tri_ClaimChg.Primary_Claim = 1)
AND (tri_IDENT.Version = 0)

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Insert Only New Items From A List But Get ID's For New And Existing In The List.

Feb 12, 2008

Hi,

I have a a table that holds a list of words, I am trying to add to the list, however I only want to add new words. But I wish to return from my proc the list of words with ID, whether it is new or old.

Here's a script. the creates the table,indexes, function and the storeproc. call the proc like procStoreAndUpdateTokenList 'word1,word2,word3'

My table is now 500000 rows and growing and I am inserting on average 300 words, some new some old.

performance is a not that great so I'm thinking that my code can be improved.

SQL Express 2005 SP2
Windows Server 2003
1GB Ram....(I know, I know)

TIA





Code Snippet
GO
CREATE TABLE [dbo].[Tokens](
[TokenID] [int] IDENTITY(1,1) NOT NULL,
[Token] [varchar](255) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
CONSTRAINT [PK_Tokens] PRIMARY KEY CLUSTERED
(
[TokenID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

CREATE UNIQUE NONCLUSTERED INDEX [IX_Tokens] ON [dbo].[Tokens]
(
[Token] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = ON, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
GO
CREATE FUNCTION [dbo].[SplitTokenList]
(
@TokenList varchar(max)
)
RETURNS
@ParsedList table
(
Token varchar(255)
)
AS
BEGIN
DECLARE @Token varchar(50), @Pos int
SET @TokenList = LTRIM(RTRIM(@TokenList ))+ ','
SET @Pos = CHARINDEX(',', @TokenList , 1)
IF REPLACE(@TokenList , ',', '') <> ''
BEGIN
WHILE @Pos > 0
BEGIN
SET @Token = LTRIM(RTRIM(LEFT(@TokenList, @Pos - 1)))
IF @Token <> ''
BEGIN
INSERT INTO @ParsedList (Token)
VALUES (@Token) --Use Appropriate conversion
END
SET @TokenList = RIGHT(@TokenList, LEN(@TokenList) - @Pos)
SET @Pos = CHARINDEX(',', @TokenList, 1)
END
END
RETURN
END
GO

CREATE PROCEDURE [dbo].[procStoreAndUpdateTokenList]
@TokenList varchar(max)
AS
BEGIN
SET NOCOUNT ON;
create table #Tokens (TokenID int default 0, Token varchar(50))
create clustered index Tind on #T (Token)
DECLARE @NewTokens table
(
TokenID int default 0,
Token varchar(50)
)

--Split ID's into a table
INSERT INTO #Tokens(Token)
SELECT Token FROM SplitTokenList(@TokenList)
BEGIN TRY
BEGIN TRANSACTION
--get ID's for any existing tokens
UPDATE #Tokens SET TokenID = ISNULL( t.TokenID ,0)
FROM #Tokens tl INNER JOIN Tokens t ON tl.Token = t.Token

INSERT INTO Tokens(Token)
OUTPUT INSERTED.TokenID, INSERTED.Token INTO @NewTokens
SELECT DISTINCT Token FROM #Tokens WHERE TokenID = 0

return the list with id for new and old
SELECT TokenID, Token FROM #Tokens
WHERE TokenID <> 0
UNION
SELECT TokenID, Token FROM @Tokens
COMMIT TRANSACTION
END TRY
BEGIN CATCH
DECLARE @er nvarchar(max)
SET @er = ERROR_MESSAGE();
RAISERROR(@er, 14,1);
ROLLBACK TRAN
END CATCH;
END
GO




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HI...



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i have two tables...



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to each dataset row i need to do an insert on the first table, get the @@Identity and insert it on the second table !!



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here is the script



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?,
?,
?,
?,
?,
?
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SELECT Artist, Title Into #TempArtistTitle FROM MediaFile GROUP BY Artist, Title
HAVING COUNT(SubString(DiscNo, 0, 3)) > 1

SELECT MediaFile.DiscNo, MediaFile.Artist, MediaFile.Title FROM MediaFile RIGHT OUTER JOIN #TempArtistTitle
ON MediaFile.Title = #TempArtistTitle.Title AND MediaFile.Artist = #TempArtistTitle.Artist
ORDER BY Artist, Title, DiscNo

Drop TABLE #TempArtistTitle
GO

See, if the first 3 characters of the disc number is the same, it is the same manufacturer. This query works somewhat, although it returns records that the discnumber is unique too. Like below, the LG disc number shouldn't be returned, as there is only one record for that artist/title.


SC8151-10 - Garth Brooks - Friends In Low Places
SC8125-04 - Garth Brooks - Friends In Low Places
LG5003-07 - Garth Brooks - Friends In Low Places


Could someone help me please?

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Select List Split By Comma

Oct 29, 2014

i have a list of data as below:

Company Email
A AAA@abc.com
A BBB@abc.com
B xxx@def.com

i would like to write a query to list out as below where select the company A
AAA@abc.com, BBB@abc.com, ...

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